Hard
Following code is compiled to executable my ‘myprog’
int main(int argc, char **argv)
{
std::cout << argc - 1 << " X " << strlen(*(argv+1) + 2) << " = " << *(*(argv+1)+3);
std::cout<<std::endl;
return 0;
}
What would be the output if the following command is given to the operating system myprog C++11 is easy?
Author: Abha AgrawaStatus: PublishedQuestion passed 420 times
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ez19/12/2023
bad c++, not in standars anymore to use these kind of syntax.
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