C++: what is the output of the following code? `std::cout

Question

Consider a class MyType which defines a public function isType() as:
 ```cpp
        	int isType (MyType& obj)
        	{
      	          	return (&obj == this) ? 1 : 0;
        	}
```
 
What is the output of the following? Object ‘obj’ of MyType is allocated statically and a pointer variable ‘objptr’ of type MyType is declared.
```cpp        	
        	objptr = &obj;
 
        	if ( objptr->isType(obj) )
	                	std::cout << "&obj and invoking object match!!!" << std::endl;
        	else
	                	std::cout << "&obj and invoking object do not match!!!" << std::endl;
```

Accepted Answer

&obj and invoking object match!!!

Answer

Compile time error, 'this' should be referenced using &

Answer

Run time error, 'this' should be referenced using &

Answer

&obj and invoking object do not match!!!

Question from the C++ test

C++: what is the output of the following code? `std::cout << &obj << std::endl;`