Order of execution of asynchronous functions with different delays in Python.

Question

Consider the following asynchronous functions:

```python
import asyncio

async def start():
    await asyncio.sleep(4)
    print("Terminé 1")

async def stop():
    await asyncio.sleep(2)
    print("Terminé 2")

async def main():
    t1 = asyncio.create_task(start())
    t2 = asyncio.create_task(stop())

await t1
    await t2

asyncio.run(main())
```

When executing the `main()` function, what can you say about the order and timing of the messages displayed by `start()` and `stop()`?

Accepted Answer

The message "Terminé 2" will appear before "Terminé 1" because the stop() function has a shorter delay and finishes sooner

Answer

The messages will appear in the order of their launch, so "Terminé 1" will appear before "Terminé 2" in the console

Answer

The messages "Terminé 1" and "Terminé 2" will appear at the same time, since asynchronous functions run simultaneously

Answer

The asynchronous functions are executed one after the other, so "Terminé 1" will appear only once "Terminé 2" has finished

Question from the Python test