What is the output of the following Ruby code?

class Foo
def initialize(z)
@z = z
end
def x
@z * 2
end
end

foo = Foo.new(1)
puts foo.x

Question

Here is a technical question for developers that want to validate their skills before a technical interview.
This question is written in french and need to be translated to english.
Use english for technical terms in the french version (example : "string" instead of "chaine de caractère".)
Double escape all quotes in result like this: //"
Give result as JSON.

Accepted Answer

foo has an instance variable @z whose value is initialized at the instantiation of the Foo class.

Accepted Answer

foo.x returns the value of @z times 2

Answer

foo.z returns the value of @z

Question from the Ruby (legacy) test

What is the output of the following Ruby code? class Foo def initialize(z) @z = z end def x @z * 2 end end foo = Foo.new(1) puts foo.x