Question

In the code above, what is the behavior of the call 's.Log()' and why?

```
type Logger struct{}
func (l Logger) Log() { fmt.Println("log") }

type Service struct {
    Logger
}
func (s Service) Log() { fmt.Println("service") }
```

Accepted Answer

Calls Service.Log() because the local method shadows the embedded one.

Answer

Causes a compilation error due to method conflict.

Answer

Calls Logger.Log() because embedding has higher priority.

Answer

Calls both methods sequentially due to automatic promotion.

Question from the Go test